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Java Multi catch block multiple exceptions

Java Multi-catch block

A try block may be followed by a single catch block or multiple. A different exception handler must be present in each catch block. Use a Java multi-catch block, then, if you need to carry out multiple tasks when various exceptions arise.

Only one catch block is executed and only one exception is raised at a time.
When handling Java exceptions, it is essential to organize catch blocks in a descending order of specificity, prioritizing the catch block for ArithmeticException before the catch block for Exception.

Flow Chart of Multi Catch Block

Java multi-catch block

public class Main {	
    public static void main(String args[]){    	  		  
	    try{   // try block  
	     int Num1 =10/0; 
	     int arr[]=new int[10]; 
	     arr[5]=15;    
	    }  
	    catch(ArithmeticException e){   
	      System.out.println(e);  
	    }  
	    catch(ArrayIndexOutOfBoundsException e){   
	       System.out.println(e);  
	    }                
	  System.out.println("This Code after outer catch block");  
   } 
}

Output:

java.lang.ArithmeticException: / by zero
This Code after outer catch block

Java multi-catch block example 2

public class Main {	
    public static void main(String args[]){    	  		  
	    try{   // try block  
	     int arr[]=new int[10]; 
	     arr[15]=15;    
	    }  
	    catch(ArithmeticException e){   
	      System.out.println(e);  
	    }  
	    catch(ArrayIndexOutOfBoundsException e){   
	       System.out.println(e);  
	    }                
	  System.out.println("This Code after outer catch block");  
   } 
}

Output:

 java.lang.ArrayIndexOutOfBoundsException: Index 15 out of bounds for length 10
This Code after outer catch block

Java multi-catch block with multiple exception

The try block in the example below has two exceptions. However, only one exception occurs at a time, and its associated catch block is executed.

public class Main {	
    public static void main(String args[]){    	  		  
	    try{   // try block  
            int arr[]=new int[10];    
            arr[15]=15/0;    
            System.out.println(arr[15]);    
	    }  
	    catch(ArithmeticException e){   
	      System.out.println(e);  
	    }  
	    catch(ArrayIndexOutOfBoundsException e){   
	       System.out.println(e);  
	    }                
	  System.out.println("This Code after outer catch block");  
   } 
}

Output:

 java.lang.ArithmeticException: / by zero
This Code after outer catch block

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Java Multi catch block multiple exceptions

Java Multi-catch block

Java multi-catch block

Java multi-catch block example 2

Java multi-catch block with multiple exception

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